Broward County, FL vs Humboldt County, CA
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
Humboldt County, CA: 0.83% effective rate · $3,362/yr median tax · median home $405,109
Side-by-Side Comparison
| Metric | Broward County, FL | Humboldt County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 0.83% | 1.06% |
| Median Annual Tax | $3,539 | $3,362 | $2,778 |
| Median Home Value | $402,176 | $405,109 | $268,728 |
| Population | 1,944,375 | 136,310 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
Humboldt County, CA
- Effective Rate
- 0.83%
- Median Annual Tax
- $3,362
- Median Home Value
- $405,109
- Population
- 136,310
Frequently Asked Questions
What is the property tax difference between Broward County and Humboldt County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. Humboldt County, CA has a rate of 0.83% with a median annual tax of $3,362. The difference is 0.05 percentage points.
Which county has higher property taxes, Broward County or Humboldt County?
Broward County, FL has the higher effective property tax rate at 0.88% compared to 0.83%.
How do Broward County and Humboldt County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and Humboldt County is below average at 0.83%.