Broward County, FL vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Broward County, FL | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 0.72% | 1.06% |
| Median Annual Tax | $3,539 | $5,391 | $2,778 |
| Median Home Value | $402,176 | $748,790 | $268,728 |
| Population | 1,944,375 | 873,965 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Broward County and San Francisco County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 0.16 percentage points.
Which county has higher property taxes, Broward County or San Francisco County?
Broward County, FL has the higher effective property tax rate at 0.88% compared to 0.72%.
How do Broward County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and San Francisco County is below average at 0.72%.