Broward County, FL vs Scott County, MN
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
Scott County, MN: 1.36% effective rate · $3,411/yr median tax · median home $250,819
Side-by-Side Comparison
| Metric | Broward County, FL | Scott County, MN | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 1.36% | 1.06% |
| Median Annual Tax | $3,539 | $3,411 | $2,778 |
| Median Home Value | $402,176 | $250,819 | $268,728 |
| Population | 1,944,375 | 149,013 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
Scott County, MN
- Effective Rate
- 1.36%
- Median Annual Tax
- $3,411
- Median Home Value
- $250,819
- Population
- 149,013
Frequently Asked Questions
What is the property tax difference between Broward County and Scott County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. Scott County, MN has a rate of 1.36% with a median annual tax of $3,411. The difference is 0.48 percentage points.
Which county has higher property taxes, Broward County or Scott County?
Scott County, MN has the higher effective property tax rate at 1.36% compared to 0.88%.
How do Broward County and Scott County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and Scott County is above average at 1.36%.