Clark County, NV vs Sandoval County, NM
Property Tax Rate Comparison 2025
Quick Answer
Clark County, NV: 0.46% effective rate · $1,019/yr median tax · median home $221,623
Sandoval County, NM: 0.84% effective rate · $1,304/yr median tax · median home $155,264
Side-by-Side Comparison
| Metric | Clark County, NV | Sandoval County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.46% | 0.84% | 1.06% |
| Median Annual Tax | $1,019 | $1,304 | $2,778 |
| Median Home Value | $221,623 | $155,264 | $268,728 |
| Population | 2,265,461 | 148,834 | — |
Clark County, NV
- Effective Rate
- 0.46%
- Median Annual Tax
- $1,019
- Median Home Value
- $221,623
- Population
- 2,265,461
Sandoval County, NM
- Effective Rate
- 0.84%
- Median Annual Tax
- $1,304
- Median Home Value
- $155,264
- Population
- 148,834
Frequently Asked Questions
What is the property tax difference between Clark County and Sandoval County?
Clark County, NV has an effective property tax rate of 0.46% with a median annual tax of $1,019. Sandoval County, NM has a rate of 0.84% with a median annual tax of $1,304. The difference is 0.38 percentage points.
Which county has higher property taxes, Clark County or Sandoval County?
Sandoval County, NM has the higher effective property tax rate at 0.84% compared to 0.46%.
How do Clark County and Sandoval County compare to the national average?
The national average effective property tax rate is 1.06%. Clark County is below average at 0.46%, and Sandoval County is below average at 0.84%.