Howard County, MD vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Howard County, MD: 1.21% effective rate · $2,901/yr median tax · median home $239,785
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Howard County, MD | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.21% | 0.72% | 1.06% |
| Median Annual Tax | $2,901 | $5,391 | $2,778 |
| Median Home Value | $239,785 | $748,790 | $268,728 |
| Population | 332,317 | 873,965 | — |
Howard County, MD
- Effective Rate
- 1.21%
- Median Annual Tax
- $2,901
- Median Home Value
- $239,785
- Population
- 332,317
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Howard County and San Francisco County?
Howard County, MD has an effective property tax rate of 1.21% with a median annual tax of $2,901. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 0.49 percentage points.
Which county has higher property taxes, Howard County or San Francisco County?
Howard County, MD has the higher effective property tax rate at 1.21% compared to 0.72%.
How do Howard County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Howard County is above average at 1.21%, and San Francisco County is below average at 0.72%.