Lee County, FL vs Sandoval County, NM
Property Tax Rate Comparison 2025
Quick Answer
Lee County, FL: 0.77% effective rate · $3,025/yr median tax · median home $392,974
Sandoval County, NM: 0.84% effective rate · $1,304/yr median tax · median home $155,264
Side-by-Side Comparison
| Metric | Lee County, FL | Sandoval County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.77% | 0.84% | 1.06% |
| Median Annual Tax | $3,025 | $1,304 | $2,778 |
| Median Home Value | $392,974 | $155,264 | $268,728 |
| Population | 760,822 | 148,834 | — |
Lee County, FL
- Effective Rate
- 0.77%
- Median Annual Tax
- $3,025
- Median Home Value
- $392,974
- Population
- 760,822
Sandoval County, NM
- Effective Rate
- 0.84%
- Median Annual Tax
- $1,304
- Median Home Value
- $155,264
- Population
- 148,834
Frequently Asked Questions
What is the property tax difference between Lee County and Sandoval County?
Lee County, FL has an effective property tax rate of 0.77% with a median annual tax of $3,025. Sandoval County, NM has a rate of 0.84% with a median annual tax of $1,304. The difference is 0.07 percentage points.
Which county has higher property taxes, Lee County or Sandoval County?
Sandoval County, NM has the higher effective property tax rate at 0.84% compared to 0.77%.
How do Lee County and Sandoval County compare to the national average?
The national average effective property tax rate is 1.06%. Lee County is below average at 0.77%, and Sandoval County is below average at 0.84%.