Montgomery County, OH vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Montgomery County, OH: 1.90% effective rate · $2,287/yr median tax · median home $120,415
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Montgomery County, OH | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.90% | 0.72% | 1.06% |
| Median Annual Tax | $2,287 | $5,391 | $2,778 |
| Median Home Value | $120,415 | $748,790 | $268,728 |
| Population | 537,309 | 873,965 | — |
Montgomery County, OH
- Effective Rate
- 1.90%
- Median Annual Tax
- $2,287
- Median Home Value
- $120,415
- Population
- 537,309
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Montgomery County and San Francisco County?
Montgomery County, OH has an effective property tax rate of 1.90% with a median annual tax of $2,287. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 1.18 percentage points.
Which county has higher property taxes, Montgomery County or San Francisco County?
Montgomery County, OH has the higher effective property tax rate at 1.90% compared to 0.72%.
How do Montgomery County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Montgomery County is above average at 1.90%, and San Francisco County is below average at 0.72%.