Montgomery County, TX vs San Joaquin County, CA
Property Tax Rate Comparison 2025
Quick Answer
Montgomery County, TX: 1.90% effective rate · $3,122/yr median tax · median home $164,366
San Joaquin County, CA: 0.64% effective rate · $3,258/yr median tax · median home $509,076
Side-by-Side Comparison
| Metric | Montgomery County, TX | San Joaquin County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.90% | 0.64% | 1.06% |
| Median Annual Tax | $3,122 | $3,258 | $2,778 |
| Median Home Value | $164,366 | $509,076 | $268,728 |
| Population | 607,391 | 779,233 | — |
Montgomery County, TX
- Effective Rate
- 1.90%
- Median Annual Tax
- $3,122
- Median Home Value
- $164,366
- Population
- 607,391
San Joaquin County, CA
- Effective Rate
- 0.64%
- Median Annual Tax
- $3,258
- Median Home Value
- $509,076
- Population
- 779,233
Frequently Asked Questions
What is the property tax difference between Montgomery County and San Joaquin County?
Montgomery County, TX has an effective property tax rate of 1.90% with a median annual tax of $3,122. San Joaquin County, CA has a rate of 0.64% with a median annual tax of $3,258. The difference is 1.26 percentage points.
Which county has higher property taxes, Montgomery County or San Joaquin County?
Montgomery County, TX has the higher effective property tax rate at 1.90% compared to 0.64%.
How do Montgomery County and San Joaquin County compare to the national average?
The national average effective property tax rate is 1.06%. Montgomery County is above average at 1.90%, and San Joaquin County is below average at 0.64%.