San Joaquin County, CA vs Scott County, MN
Property Tax Rate Comparison 2025
Quick Answer
San Joaquin County, CA: 0.64% effective rate · $3,258/yr median tax · median home $509,076
Scott County, MN: 1.36% effective rate · $3,411/yr median tax · median home $250,819
Side-by-Side Comparison
| Metric | San Joaquin County, CA | Scott County, MN | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.64% | 1.36% | 1.06% |
| Median Annual Tax | $3,258 | $3,411 | $2,778 |
| Median Home Value | $509,076 | $250,819 | $268,728 |
| Population | 779,233 | 149,013 | — |
San Joaquin County, CA
- Effective Rate
- 0.64%
- Median Annual Tax
- $3,258
- Median Home Value
- $509,076
- Population
- 779,233
Scott County, MN
- Effective Rate
- 1.36%
- Median Annual Tax
- $3,411
- Median Home Value
- $250,819
- Population
- 149,013
Frequently Asked Questions
What is the property tax difference between San Joaquin County and Scott County?
San Joaquin County, CA has an effective property tax rate of 0.64% with a median annual tax of $3,258. Scott County, MN has a rate of 1.36% with a median annual tax of $3,411. The difference is 0.72 percentage points.
Which county has higher property taxes, San Joaquin County or Scott County?
Scott County, MN has the higher effective property tax rate at 1.36% compared to 0.64%.
How do San Joaquin County and Scott County compare to the national average?
The national average effective property tax rate is 1.06%. San Joaquin County is below average at 0.64%, and Scott County is above average at 1.36%.